Question

For a particle executing simple harmone motion, the kinetic energy k is given by $k=k_0{\cos }^2\omega t$. The maximum value of potential energy is?

• A. $k_0$
• B. zero
• C. $k_0/2$
• D. not obtainable

Answer 1

The correct option is A $k_0$

$K=K_0=$ total energy
As total energy remains conserved itself hence when U is maximum in SHM, K$=0$
i.e., E is also equal to $U_{max}$ i.e.,
$U_{max}=E=K_0$.