For a particle executing simple harmonic motion, the acceleration is proportional to
(a) displacement from the mean position
(b) distance from the mean position
(c) distance travelled since t = 0
(d) speed

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Solution

(a) displacement from the mean position

For S.H.M.,
F = -kx
ma = - kx (F = ma)
or,
a = $- \frac{k}{m} x$
Thus, acceleration is proportional to the displacement from the mean position but in opposite direction.

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For a particle executing simple harmonic motion, the acceleration is proportional to (a) displacement from the mean position (b) distance from the mean position (c) distance travelled since t = 0 (d) speed

(a) displacement from the mean position For S.H.M., F = -kx ma = - kx (F = ma) or, a = -kmx Thus, acceleration is proportional to the displacement from the mean position but in opposite direction.

For a particle executing simple harmonic motion, the acceleration is proportional to
(a) displacement from the mean position
(b) distance from the mean position
(c) distance travelled since t = 0
(d) speed

(a) displacement from the mean position

For S.H.M.,
F = -kx
ma = - kx (F = ma)
or,
a = $- \frac{k}{m} x$
Thus, acceleration is proportional to the displacement from the mean position but in opposite direction.