Question

For a particle executing simple harmonic motion, the kinetic energy K is given by K = $K_{0}co{s}^2\omega t$ . The maximum value of potential energy is

• A.
• B. Zero
• C.
• D. Not obtainable

Answer 1

The correct option is A

Since maximum value of $co{s}^2\omega t$ is 1 .

$\therefore K_{max}=K_{0}co{s}^2\omega t=K_0$

Also $K_{max}=P{E}_{max}=K_0$