Question

For a particle executing simple harmonic motion, the kinetic energy K is given by :

$K=K_0$ $co{s}^2\omega T$. The maximum value of potential energy is

• A. $K_0$
• B. zero
• C. $K_0/2$
• D. not obtainable

Answer 1

The correct option is A $K_0$

For a particle executing simple harmonic motion, the kinetic energy is given by

$K=K_{0}co{s}^2\omega t$

We know that, $K_{max}=U_{max}$. . . . .(1)

For maximum kinetic energy, $co{s}^2\omega t=1$

$K_{max}=K_0$

from equation (1),

The maximum potential energy,

$U_{max}=K_0$

The correct option is A.