MyQuestionIcon

3

You visited us 3 times! Enjoying our articles? Unlock Full Access!

V-t to a-t Graph

For a particl...

Question

For a particle in S.H.M. the amplitude and maximum velocity are A and $v$ respectively. Then its maximum acceleration is :

A

v^{2}

/2A

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

v^{2}

A

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

v^{2}

/A

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

D

v

/A.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D $v^{2}$ /A
$x = A s i n ω t$
$v = A ω c o s ω t$
$a = - A ω^{2} s i n ω t$
So, as given in problem
$A = A$
$A ω = v$
so, $A ω^{2} = \frac{A ω (A ω)}{A} = \frac{v . v}{A} = \frac{v^{2}}{A}$

Suggest Corrections

thumbs-up

0

Similar questions

Q. A particle is travelling with uniform acceleration of magnitude a. During successive time intervals of

Δ t_{1}, Δ t_{2}

Δ t_{3}

, its average velocities are

v_{1}, v_{2}

v_{3}

respectively. Then,

Q. A point moving with constant acceleration from

A

B

in the straight line

A B

u

v

A

B

respectively. Find its velocity at

C

, the mid point of

A B

.

Q. A particle executing SHM has velocities

u

v

and accelerations

a

b

at two of its positions. Find the shortest distance between these two positions.

Q. A particle is executing S.H.M. with amplitude

^{'} a^{'}

and has maximum velocity

^{'} v^{'}

. Its speed at displacement

a / 2

Q. The velocity

v

of a particle moving along a straight line and its distance

s

from a fixed point on the line are related by

v^{2} = a^{2} + s^{2}

, then its acceleration equals

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Aftermath of SHM

PHYSICS

Watch in App

explore_more_icon

Explore more

V-t to a-t Graph

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon