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Standard XII

Physics

Horizontal and Vertical Components of Projectile Motion

For a particl...

Question

For a particle projected upwards to a height $h$ , the ascending and descending times are $t_{1}$ and $t_{2}$ respectively. The velocity of projection will be

g (t_{1} + t_{2})

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\frac{g (t_{1} + t_{2})}{2}

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g t_{2}

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g t_{1}

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Solution

The correct option is B $\frac{g (t_{1} + t_{2})}{2}$
As $t_{1}$ and $t_{2}$ are the time of ascent and descent respectively.\
So, time of flight, $T = t_{1} + t_{2} = \frac{2 u}{g}$
$u = \frac{g (t_{1} + t_{2})}{2}$ .

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For a particle projected upwards to a height h, the ascending and descending times are t1 and t2 respectively. The velocity of projection will be

The correct option is B g(t1+t2)2As t1 and t2 are the time of ascent and descent respectively.\So, time of flight, T=t1+t2=2ugu=g(t1+t2)2.

For a particle projected upwards to a height $h$ , the ascending and descending times are $t_{1}$ and $t_{2}$ respectively. The velocity of projection will be

The correct option is B $\frac{g (t_{1} + t_{2})}{2}$
As $t_{1}$ and $t_{2}$ are the time of ascent and descent respectively.\
So, time of flight, $T = t_{1} + t_{2} = \frac{2 u}{g}$
$u = \frac{g (t_{1} + t_{2})}{2}$ .