For a particle showing motion number under the force $F = - 5 {(x - 2)}^{2}$ , the motion is

Translatory

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Oscillatiory

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SHM

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All of these

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Solution

The correct option is A Translatory
Given,

$F = - 5 (x - 2)^{2}$

for $x < 0 \to F \to + v e$

for $x > 0 \to F \to - v e$

for $x = 0 \to F$ is in mean position.

F always acts towards mean position

motion is oscillatory and periodic but not SHM

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For a particle showing motion number under the forceF=−5(x−2)2 , the motion is

The correct option is A TranslatoryGiven,F=−5(x−2)2for x<0→F→+vefor x>0→F→−vefor x=0→F is in mean position.F always acts towards mean positionmotion is oscillatory and periodic but not SHM

For a particle showing motion number under the force $F = - 5 {(x - 2)}^{2}$ , the motion is

The correct option is A Translatory
Given,

$F = - 5 (x - 2)^{2}$

for $x < 0 \to F \to + v e$

for $x > 0 \to F \to - v e$

for $x = 0 \to F$ is in mean position.

F always acts towards mean position

motion is oscillatory and periodic but not SHM