For a particle undergoing linear SHM about x=0 ,choose the correct possible combination.Symbols have their usual meaning
Open in App
Solution
For (D)v×a=0 Since, angle between acceleration and velocity vector is either 0 or 180 which gives →v×→a=0 Therefore, there is no option for (D) it is never true For (A)It is true when →v and →aare in same direction and there magnitude is also non zero. Therefore, it is true everywhere else extreme and mean position therefore,
A->3,4 (B)Velocity v>0 as well as v<0 except at extreme positions where velocity v=0 B->2,3,4 (C) acceleration a<0 for 0<x≤A and at extreme position therefore, C->1,3