Question

For a particle undergoing simple harmonic motion, the velocity is plotted against displacement. The curve will be

• A. a straight line
• B. a parabola
• C. a circle
• D. an ellipse

Answer 1

The correct option is D an ellipse

$v=\omega \sqrt{A^2-x^2}$
$\therefore$ $\frac{v^2}{{\omega }^2}+\frac{x^2}{{\left(1\right)}^2}=A^2$
Hence $v-x$ graph is an ellipse.