Question

For a pavement slab of width 7 m, thickness 20 cm with a longitudinal joint along centre, the area of steel required per metre length of joint is (Coefficient of friction = 1.5; unit weight of CC pavement $=2400kg/m^3;$ allowable working stress in steel =$1400kg/c{m}^2)$

• A. $3.6c{m}^2$
• B. $1.8c{m}^2$
• C. $18c{m}^2$
• D. $36c{m}^2$

Answer 1

The correct option is B $1.8c{m}^2$

Area of steel rquired $\left(inc{m}^2\right)$ per metre length of longitudinal joint is given by
$A_S=\frac{bfhW}{S}$
b = distance between the joint and nearest free edge in metre
$=\frac{7}{2}=3.5m$
f = friction coefficient = 1.5
h = thickness of pavement in = 20 cm = 0.2 m
W = unit weight of CC pavement in kg/cu.m = 2400
S = allowable working stress in steel in kg/sq.cm = 1400
Area of steel required $\left(inc{m}^2\right)$ per metre length
$A_S=\frac{3.5\times 1.5\times 0.2\times 2400}{1400}=1.8\frac{c{m}^2}{m}$