Question

For a pavement slab of width 7m, thickness 20 cm with a longitudinal joint along center the area of steel required per meter length of joint is (coefficient of friction = 1.5; unit weight of CC pavement = 2400 kg/m${}^3$), allowable working stress in steel = 1400 kg/cm${}^2$

• A. $3.6c{m}^2$
• B. $18c{m}^2$
• C. $1.8c{m}^2$
• D. $36c{m}^2$

Answer 1

The correct option is C $1.8c{m}^2$

Area of steel required $\left(inc{m}^2\right)$ per metre length of longitudinal joint is given by
$A_s=\frac{bfhW}{100S}$
b = distance between the joint and nearest free edge in metre = 7/2 = 3.5m
f = friction coefficient = 1.5
W = unit weight of CC pavement in kg/cu.m = 2400
S = allowable working stress in steel in kg/sq.cm = 1400
Area of steel required in sq.cm per metre length
$A_s=\frac{3.5\times 1.5\times 20\times 2400}{100\times 1400}=1.8c{m}^2/m$