Question

For a phase change:
$H_{2}O\left(l\right)\rightleftharpoons H_{2}O\left(s\right)$
$0^{o}C,1$ bar

• A. $\Delta G=0$
• B. $\Delta S=0$
• C. $\Delta H=0$
• D. $\Delta U=0$

Answer 1

Answer: (A)

$\Delta G=0$

The phase change, $H_{2}O\left(l\right)\rightleftharpoons H_{2}O\left(s\right)$ is a equilibrium process. At equilibrium, the value of Gibb's free energy $\left(\Delta G\right)=0$, at standard conditions.

$\therefore$ For a phase change : $H_{2}O\left(l\right)\rightleftharpoons H_{2}O\left(s\right)$ at $O^{0}C$ & 1 bar, $\Delta G=0$