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Question

For a projectile projected from ground at an angle θ with horizontal, gT2=2R3, where T is time of fight, R is horizontal range of projectile, g is acceleration due to gravity. The angle of projection (θ) is

A
30
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B
60
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C
45
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D
90
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Solution

The correct option is A 30
According to question: gT2=2R3g(2usinθg)2=23u2sin2θg
g(4u2sin2θg2)=23×u2sin2θg
4u2sin2θg=23×u2×2sinθcosθg
On solving we get tanθ=13θ=30

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