For a pure substance, a plot of Gibbs' free energy (G) against temperature at constant pressure and Gibbs' free energy (G) against pressure and constant temperature are respectively:

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Solution

The correct options are
B
C
According to thermodynamics,
$d G = - S d T + V d P$

at constant $P$ ,
$d G = - S d T$
So the plot of $G$ versus $T$ is a straight line with slope = $- S$

at constant $T$ ,
$d G = V d P$
So the plot of $G$ versus $P$ is a straight line with slope = $V$

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For a pure substance, a plot of Gibbs' free energy (G) against temperature at constant pressure and Gibbs' free energy (G) against pressure and constant temperature are respectively:

The correct options are B C According to thermodynamics, dG=−SdT + VdP at constant P, dG=−SdT So the plot of G versus T is a straight line with slope = −S at constant T, dG=VdP So the plot of G versus P is a straight line with slope = V

The correct options are
B
C
According to thermodynamics,
$d G = - S d T + V d P$

at constant $P$ ,
$d G = - S d T$
So the plot of $G$ versus $T$ is a straight line with slope = $- S$

at constant $T$ ,
$d G = V d P$
So the plot of $G$ versus $P$ is a straight line with slope = $V$