Question

For a quadratic equation $a{x}^2+bx+c=0,a\ne 0$, if $c=0$ then the roots of the equation are

• A. $\{1,-\frac{b}{a}\}$
• B. $\{1,-\frac{a}{b}\}$
• C. $\{0,-\frac{b}{a}\}$
• D. $\{0,-\frac{a}{b}\}$

Answer 1

The correct option is C $\{0,-\frac{b}{a}\}$

In $a{x}^2+bx+c=0,a\ne 0,$ if $c=0$ then we have
$\Rightarrow a{x}^2+bx=0$
$\Rightarrow x(ax+b)=0$
Hence roots are $0$ and $-\frac{b}{a}$