Question

For a quadratic equation, if one of the root is $\sqrt{2}+\sqrt{3}$, then the equation is $x^2-2\sqrt{2}x-1=0$

• A. True
• B. False

Answer 1

The correct option is A True

If one root is $\sqrt{2}+\sqrt{3}$ then the other root will be $\sqrt{2}-\sqrt{3}$
Sum of root $=2\sqrt{2}$
Product of roots $=(\sqrt{2}+\sqrt{3})(\sqrt{2}-\sqrt{3})=2-3=-1$
The equation whose standard form is $x^2-Sx+P=0$ will be $x^2-2\sqrt{2}x-1=0$