For a quadratic equation of the form $a x^{2} + b x + c = 0$ the solutions are $x_{1, 2} = \frac{- b \pm \sqrt{b^{2} - 4 a c}}{2 a}$

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Solution

$F o r a = 1, b = 10, c = - 25 : t_{1, 2} = \frac{- (- 10) \pm \sqrt{(- 10)^{2} - 4. 1 (- 25)}}{2.1} t = \frac{- (- 10) + \sqrt{(- 10)^{2} - 4.1 (- 25)}}{2.1} : 5 (1 + \sqrt{2}) t = \frac{- (- 10) - \sqrt{(- 10)^{2} - 4.1 (- 25)}}{2.1} : 5 (1 - \sqrt{2})$
The final solutions to the quadratic equation are :
$t = 5 (1 + \sqrt{2}), t = 5 (1 - \sqrt{2})$

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For a quadratic equation of the form ax2+bx+c=0 the solutions are x1,2=−b±√b2−4ac2a

For a=1,b=10,c=−25:t1,2=−(−10)±√(−10)2−4.1(−25)2.1t=−(−10)+√(−10)2−4.1(−25)2.1:5(1+√2)t=−(−10)−√(−10)2−4.1(−25)2.1:5(1−√2) The final solutions to the quadratic equation are : t=5(1+√2),t=5(1−√2)

For a quadratic equation of the form $a x^{2} + b x + c = 0$ the solutions are $x_{1, 2} = \frac{- b \pm \sqrt{b^{2} - 4 a c}}{2 a}$