For a quadrilateral ABCD , if 3,4,5 and 6 points are marked on the sides AB,BC,CD and DA respectively. Then number of triangles that can be formed with vertices on different sides, is
A
270
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B
342
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C
282
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D
252
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Solution
The correct option is B342 Required triangle must have one point on each side of Quadrilateral.
Hence the required number of triangles =3C1×4C1×5C1+3C1×4C1×6C1+3C1×5C1×6C1+4C1×5C1×6C1 =342