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Byju's Answer
Standard XII
Mathematics
Standard Deviation about Mean for Continuous Frequency Distributions
For a random ...
Question
For a random variable
X
. If
E
(
X
)
=
5
and
V
(
X
)
=
6
, then
E
(
X
2
)
is equal to
A
19
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B
31
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C
61
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D
11
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Solution
The correct option is
B
31
As we know that,
V
(
X
)
=
E
(
X
2
)
−
(
E
(
X
)
)
2
∴
6
=
E
(
X
2
)
−
5
2
⇒
E
(
X
2
)
=
6
+
25
=
31
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0
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