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Question

For a reaction 2A+B2AB, it is found that doubling the concentration of both the reactants the rate increases to 8 times that of initial rate but doubling the concentration of B alone doubles the rate. Then the order of the reaction with respect to A and B are :

A
0,3
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B
0,2
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C
2,1
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D
2,2
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Solution

The correct option is D 2,1
For the given reaction,
2A+B2AB
Rate =r= k[A]m[B]n .........(i), where m= order with respect to A & n= order with respect to B

Given that rate =8r= k[2A]m[2B]n ........(ii)

Also, rate =2r= k[A]m[2B]n ......(iii)

On dividing (ii) by (iii), we get

8r2r=k[2A]m[2B]nk[A]m[2B]n

22=2m & hence, m=2

Next divide (i) by (iii), we get

r2r=k[A]m[B]nk[A]m[2B]n

[12]1=[12]n & hence, n=1.
Hence, order with respect to A and B is 2 and 1 respectively.

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