For a reaction : A+B→ Products, the rate of the reaction at various concentrations are given below:
Expt No
[A]
[B]
rate (mol dm−3s−1)
1
0.2
0.2
2
2
0.2
0.4
4
3
0.6
0.4
36
The rate law for the above reaction is :
A
r=K[A]2[B]
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B
r=K[A][B]2
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C
r=K[A]3[B]
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D
r=K[A]2[B]2
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Solution
The correct option is Ar=K[A]2[B] From second and third experiment, we observe that when the concentration of B is kept constant at 0.4 M and the concentration of A is trebled from 0.2 M to 0.6 M, the rate increases 9 times from 4 to 36. Hence, the order of the reaction with respect to A is 2. From first and second experiment, we observe that when the concentration of A is kept constant at 0.2 M and the concentration of A is doubled from 0.2 M to 0.4 M, the rate doubles from 2 to 4. Hence, the order of the reaction with respect to B is 1. The rate law for the reaction is r=K[A]2[B]