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Question

For a reaction AP, the plots of [A] and [P] with time temperatrues T1 and T2 are given below.

If T2>T1, the correct statement(s) is (are) (Assume ΔHθ and ΔSθ are independent of temperature and ratio of ln K at T1 to lnK at T2 is greater than T2T1. Here H, S, G and K are enthalpy, entropy, Gibbs energy and equilibrium constant, respectively.)


A
ΔHθ<0,ΔSθ<0
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B
ΔGθ<0,ΔHθ>0
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C
ΔGθ<0,ΔSθ<0
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D
ΔGθ<0,ΔSθ>0
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Solution

The correct options are
A ΔHθ<0,ΔSθ<0
C ΔGθ<0,ΔSθ<0
AP
(P)eq>5,(A)eq<5
Keq=[P][A]>1
ΔG0=RT ln Keq,ΔG0<0
ln KT1ln KT2>T2T1>1
KT1KT2>1
KT2<KT1 (exothermic)
ΔH0<0, since (P) at T2 < at T1
ΔG0=ΔH0TΔS0
TΔS0=ΔH0ΔG0
ΔS0=ΔH0ΔG0T;(ΔH0)>(ΔG0)
ΔS0<0
Also, T1 ln KT1<T2 ln KT2
ΔG0T1<ΔG0T2
ΔH0T1TΔS0T1<ΔH0T2TΔS0T2
It is possible only if ΔS0<0.

Chemistry

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