For a reaction at 25∘C enthalpy change (ΔH) and entropy change (ΔS) are −11.7×103Jmol−1 and −105Jmol−1K−1 respectively. The reaction is:
A
spontaneous.
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B
non spontaneous.
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C
at equilibrium.
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D
can't say anything.
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Solution
The correct option is B non spontaneous. Spontaneous reactions have negative free energy change and non spontaneous reactions have positive free energy change.
ΔG=ΔH−TΔS. Substitute values in the above expression.
ΔG=−11.7×103Jmol−1−298K×−105Jmol−1K−1=19590Jmol−1
Since, the gibbs free energy change is positive, the reaction is non spontaneous.