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Arrhenius Equation

For a reactio...

Question

For a reaction, given below is the graph of $l n k vs \frac{1}{T}$ . The activation energy for the reaction is equal to $c a l m o l^{- 1}$ . (Nearest integer)

(Given: $R = 2 c a l K^{- 1} m o l^{- 1}$ )

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Solution

$Slope = \frac{- 20}{5}$

$l n k = l n A - \frac{E_{a}}{R T}$

$∴ \frac{E_{a}}{R} = \frac{20}{5} \Rightarrow \frac{20 R}{5} = 8 c a l m o l^{- 1}$

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