For a reaction $H_{2}$ + $I_{2}$ $⇌$ 2HI at 721 K, the value of equilibrium constant is 50. If 0.5 moles each of $H_{2}$ and $I_{2}$ is added to the system the value of equilibrium constant will be

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Solution

The correct option is C 50
The equilibrium reaction is $H_{2} (g) + I_{2} (g) \to 2 H I (g)$ .
The relationship between Kp and Kc is $K p = K c (R T)^{Δ n}$ .
For the equilibrium reaction, Δn=2−(1+1)=0.
Hence, Kp =Kc =50.

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