For a reaction- I - -O Cl - - I O - - Cl - in an aqueous medium- the rate of the reaction is given by- d- I O - - dt -k- I - - - O Cl - - - O H - -The overall order of the reaction is-

The correct option is D 1 Rate= d[I_0^ ]/dt =k[I^ ]^1[OCl^ ]^1[OH^ ]^ 1 overall order of the reaction =1+1 1=1 ...

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Order of Reaction

For a reactio...

Question

For a reaction, $I^{-} + O {C l}^{-} ⟶ I O^{-} + {C l}^{-}$ , in an aqueous medium, the rate of the reaction is given by, $\frac{d [I O^{-}]}{d t} = k \frac{[I^{-}] [O {C l}^{-}]}{[O H^{-}]}$ .
The overall order of the reaction is:

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I^{-} + O C l^{-} \to I O^{-} + C l^{-}

\frac{d [I O^{-}]}{d t} = k \frac{[I^{-}] [O C l^{-}]}{[O H^{-}]}

I^{-} + O C l^{-} \to I O^{-} + C l^{-}

\frac{d [I O^{-}]}{d t} = K \frac{[I^{-}] [O C l^{-}]}{[O H^{-}]}

O C l^{+} + l^{-} {O H}^{-} - -- \to O l^{-} + C l^{-}

r = k [O C l^{-}] [I^{-}] [O H^{-}]^{- 1}

O H^{-}

I^{-} (a q) + O C l^{-} \to I O^{-} (a q) + C l^{-} (a q)

For the chemical reaction $l^{⊖} + O C l^{⊖} \to C l^{⊖} + O I^{⊖}$

$R a t e = \frac{k [O C l^{⊖}] [l^{⊖}]}{[O H]^{⊖}}$ The order and molecularity of the reaction is:

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