Question

For a reaction if $K_p>K_c$, the forward reaction is favoured by:

• A. low pressure
• B. high pressure
• C. high temperature
• D. low temperature

Answer 1

The correct option is A low pressure

For a reaction if $K_p>K_c$, the forward reaction is favoured by low pressure.

$K_p=K_c(RT{)}^{\Delta n}$

Since $K_p>K_c$

$\therefore \Delta n>0$, i.e. product side contains more particles than the reactant side.

At low pressure, the equilibrium will shift in the forward direction so that more and more gaseous products are formed. This will increase the total pressure and nullify the effect of low pressure.