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Oxidising Reagent and Reducing Reagent

For a reactio...

Question

For a reaction
$M^{x +} + M n O_{4}^{-} \to M O_{3}^{-} + M n^{2 +} + \frac{1}{2} O_{2}$
If 1 mole of $M n O_{4}^{-}$ oxidises 1.66 moles of $M^{x +}$ to $M O_{3}^{-}$ , then the value of x in the reaction is

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Solution

Since 1 mole of $M n O_{4}^{-}$ oxidises 1.67 moles of $M^{x +}$ , so from gm. equivalent concept
$1.66 \times n-factor of M = 1 \times 5$
$\Rightarrow n-factor of M = 3$
$∴ 5 - x = 3 \Rightarrow x = 2$

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