For a reaction pA - qB - Products- the rate law expression is r - k-A- -B-m- Then-

The correct option is C (p + q) may or may not be equal to (1 + m)(p + q) may or may not be equal to (1 + m). #160;p and q are the stoichiometric coefficient ...

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Standard XII

Chemistry

Mole Concept

For a reactio...

Question

For a reaction pA + qB $\to$ Products, the rate law expression is r = k[A] $[B]^{m}$ , Then:

(p + q)

=

(1 + m)

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(p + q)

>

(1 + m)

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(p + q) may or may not be equal to (1 + m)

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(p + q)

\neq

(1 + m)

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Solution

The correct option is C (p + q) may or may not be equal to (1 + m)
(p + q) may or may not be equal to (1 + m).

p and q are the stoichiometric coefficients in the balanced chemical equation and l and m are the orders of reaction with respect to A and B respectively. p and q can differ from l and m.

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For a reaction pA + qB → Products, the rate law expression is r = k[A][B]m, Then:

The correct option is C (p + q) may or may not be equal to (1 + m)(p + q) may or may not be equal to (1 + m). p and q are the stoichiometric coefficients in the balanced chemical equation and l and m are the orders of reaction with respect to A and B respectively. p and q can differ from l and m.

For a reaction pA + qB $\to$ Products, the rate law expression is r = k[A] $[B]^{m}$ , Then:

The correct option is C (p + q) may or may not be equal to (1 + m)
(p + q) may or may not be equal to (1 + m).

p and q are the stoichiometric coefficients in the balanced chemical equation and l and m are the orders of reaction with respect to A and B respectively. p and q can differ from l and m.