For a reaction $R \to P$ , the concentration of a reactant changes from $0.05 M$ to $0.04 M$ in $30$ minutes. What will be the average rate of reaction in minutes?

4 \times 10^{- 4} M m i n^{- 1}

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8 \times 10^{- 4} M m i n^{- 1}

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3.3 \times 10^{- 4} M m i n^{- 1}

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2.2 \times 10^{- 4} M m i n^{- 1}

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Solution

The correct option is C $3.3 \times 10^{- 4} M m i n^{- 1}$
Average rate $= - \frac{△ [R]}{△ t} = - \frac{([R]_{2} - [R]_{1})}{t_{2} - t_{1}}$

$= - \frac{(0.04 - 0.05)}{30} = \frac{0.01}{30}$

$= 3.3 \times 10^{- 4} M m i n^{- 1}$ .

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For a reaction R→P, the concentration of a reactant changes from 0.05 M to 0.04 M in 30 minutes. What will be the average rate of reaction in minutes?

The correct option is C 3.3×10−4M min−1Average rate =−△[R]△t=−([R]2−[R]1)t2−t1=−(0.04−0.05)30=0.0130=3.3×10−4M min−1.

For a reaction $R \to P$ , the concentration of a reactant changes from $0.05 M$ to $0.04 M$ in $30$ minutes. What will be the average rate of reaction in minutes?

The correct option is C $3.3 \times 10^{- 4} M m i n^{- 1}$
Average rate $= - \frac{△ [R]}{△ t} = - \frac{([R]_{2} - [R]_{1})}{t_{2} - t_{1}}$

$= - \frac{(0.04 - 0.05)}{30} = \frac{0.01}{30}$

$= 3.3 \times 10^{- 4} M m i n^{- 1}$ .