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Byju's Answer
Standard XII
Chemistry
Characteristics of Equilibrium Constant
For a reactio...
Question
For a reaction, the rate constant is expressed as,
k
=
A
.
e
−
40000
/
T
.
The energy of the activation in calorie is:
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Solution
As we know,
k
=
A
e
−
E
a
/
R
T
So by comparison,
−
E
a
R
=
−
40000
E
a
=
40000
×
2
=
8
×
10
4
c
a
l
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Similar questions
Q.
For a reaction, the rate constant is expressed as,
k
=
A
.
e
−
40000
/
T
.
The energy of the activation is:
Q.
For a reaction, the rate constant is expressed as
k
=
A
e
−
40000
/
T
. The energy of the activation is:
Q.
For a given reaction at temperature
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k
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′
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Given,
R
=
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c
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l
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−
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m
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−
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. Calculate the value of energy of activation.
Q.
The rate constant for decomposition of
C
O
C
l
2
(
g
)
according to following reaction
C
O
C
l
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(
g
)
→
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g
)
+
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l
2
(
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Δ
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k
c
a
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/
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o
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, expressed as
l
n
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=
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T
Calculate activation energy for given reaction.
(
i
n
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c
a
l
/
m
o
l
)
.
Q.
(i) Write the mathematical expression relating the variation of rate constant of a reaction with temperature.
(ii) How can you graphically find the activation energy of the recation from the Arrhenius expression?
(iii) The slope of the line in the graph of log k(k=rate constant) versus
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