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Spontaneity

For a reactio...

Question

For a reaction to be spontaneous at any temperature, the conditions are:

Δ

H = +ve,

Δ

S = +ve

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Δ

H = -ve,

Δ

S = -ve

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Δ

H = +ve,

Δ

S = -ve

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Δ

H = -ve,

Δ

S = +ve

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Solution

The correct option is C $Δ$ H = -ve, $Δ$ S = +ve
$Δ G = Δ H - T Δ S$
If $Δ H$ = negative and $Δ S$ is positive , then for any value of T , $Δ G$ will be negative and the process will be spontaneous.

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\begin{matrix} Δ H & Δ S & Temperature & Spontanity I. & \oplus v e & ⊖ v e & Any temperature & Non-spontaneous II. & ⊖ v e & ⊖ v e & Low temperature & Non-spontaneous III. & \oplus v e & \oplus v e & Low temperature & Spontaneous IV. & ⊖ v e & \oplus v e & Any temperature & Spontaneous \end{matrix}

\begin{matrix} Δ H & Δ S & Temperature & Spontaneity I. & \oplus v e & ⊖ v e & Any temperature & Non-spontaneous II. & ⊖ v e & ⊖ v e & Low temperature & Non-spontaneous III. & \oplus v e & \oplus v e & Low temperature & Spontaneous IV. & ⊖ v e & \oplus v e & Any temperature & Spontaneous \end{matrix}

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