For a reaction to be spontaneous with a positive enthalpy and a positive entropy value, the temperature should be :
A
low
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B
high
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C
this combination will always be spontaneous
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D
All temperatures
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E
this combination will always be non spontaneous
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Solution
The correct option is A high ΔG=ΔH−TΔS, For ΔH to be positive and positive entropy (ΔS) , the product of the T and ΔS must have the higher negative value than the ΔH numerical positive value. Hence, T must be high.