Question

For a reaction $X+2Y\to Z$, number of mole of $Z$ formed by starting the reaction with 4 moles of $X$ and 6 moles of $Y$ is:

• A. 2
• B. 3
• C. 4
• D. 6

Answer 1

Answer: (B)

3

$X+24⟶Z$

$I$ $4$ $6$ $?$

$1$ mole of $X$ combines with $2$ moles of $Y$ to give $1$ mole of $Z$.

Hence $4$ moles of $X$ needs $8$ moles of $Y$.

So, $7$ is limiting reactant.

$\therefore$ Only $3$ moles of $X$ reacts with $6$ moles of $Y$ to give $3$ moles of $Z$.