Question

For a reaction: $XA\to YB$, if $log[-\frac{dA}{dt}]=log\left[\frac{dB}{dt}\right]+0.3$, then the ratio of $Y:X$ is:

• A. $\frac{1}{2}$
• B. $2$
• C. $\frac{1}{3}$
• D. $3$

Answer 1

The correct option is A $\frac{1}{2}$

$-\frac{1}{X}\frac{d\left[A\right]}{dt}=\frac{1}{Y}\frac{d\left[B\right]}{dt}$

$log-\frac{d\left[A\right]}{dt}=log\frac{d\left[B\right]}{dt}+log\frac{X}{Y}$

$\therefore log\frac{X}{Y}=0.3$

$\frac{X}{Y}=2.0$