Question

For a reaction: $xA+yB\to zC$, if $-\frac{d\left[A\right]}{dt}=-\frac{d\left[B\right]}{dt}=1.5\frac{d\left[C\right]}{dt}$; then $x,y$ and $z$ are:

• A. $1,1,1$
• B. $3,2,3$
• C. $3,3,2$
• D. $2,2,3$

Answer 1

Answer: (C)

$3,3,2$

$-\frac{1}{x}\frac{d\left[A\right]}{dt}=-\frac{1}{y}\frac{d\left[B\right]}{dt}=\frac{1}{z}\frac{d\left[c\right]}{dt}$

Comparing given equation with the given equation we get,

$x=y=\frac{z}{1.5}$

So we multiply the whole equation with $3$

$3x=3y=\frac{z}{1.5}\times 3$

So we get,

$x=3$

$y=3$

$z=2$