For a real gas mol- mass - 30 if density at critical point is 0-04 g-cm3 and its Tc - 2- 10821K- then calculate Van der Waals constant a in atm L2mol-2-

T_c=8a27Rb, V_c=3b V_c=0.0430=3b b=0.0430=3b T_c b =0.0490(10^ 3) L^ 1m^ 3 40/90(10)L^ 1=b 2× 10821=8× 1× 927× R× 4 30R8 ...

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Standard XII

Chemistry

Real Gases

For a real ga...

Question

For a real gas $(m o l . m a s s = 30)$ if density at critical point is $0.04 g / c m^{3}$ and its $T_{c} = \frac{2 \times 10}{821} K$ , then calculate Van der Waals constant a (in $a t m L^{2} m o l^{- 2}$ ).

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Solution

$T_{c} = \frac{8 a}{27 R b}, V_{c} = 3 b$
$V_{c} = \frac{0.04}{30} = 3 b$
$b = \frac{0.04}{30} = 3 b$
$T_{c} b = \frac{0.04}{90 (10^{- 3})} L^{- 1} m^{- 3}$
$\frac{40}{90 (10)} L^{- 1} = b$
$\frac{2 \times 10}{821} = \frac{8 \times 1 \times 9}{27 \times R \times 4}$
$\frac{30 R}{821} = a = \frac{30 \times 0.0821}{821} = 3 \times 10^{- 3}$

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For a real gas (mol. mass=30) if density at critical point is 0.04 g/cm3 and its Tc=2×10821K, then calculate Van der Waals constant a (in atm L2mol−2).

Tc=8a27Rb,Vc=3bVc=0.0430=3bb=0.0430=3bTcb=0.0490(10−3)L−1m−34090(10)L−1=b2×10821=8×1×927×R×430R821=a=30×0.0821821=3×10−3

For a real gas $(m o l . m a s s = 30)$ if density at critical point is $0.04 g / c m^{3}$ and its $T_{c} = \frac{2 \times 10}{821} K$ , then calculate Van der Waals constant a (in $a t m L^{2} m o l^{- 2}$ ).