For a received amplitude modulated signal, let $f_{r}$ be the center frequency of the received signal, $f_{I}$ be the intermediate frequency and $f_{m}$ be the frequency of the demodulated signal. Then, choose the correct option:

f_{r} < f_{I} < f_{m}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

f_{m} < f_{I} < f_{r}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

f_{r} < f_{m} < f_{I}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

f_{m} < f_{r} < f_{I}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D $f_{m} < f_{I} < f_{r}$
For the amplitude modulation the carrier frequency remains the same but the actual frequency changes and goes down.
The center frequency then the intermediate frequency and then finally the demodulated frequency

Suggest Corrections

Similar questions

π

f (r + s) = f (r) + f (s) \forall r, s \in R

m

n

f (\frac{n}{m})

k_{f} = 1 k H z / V

Join BYJU'S Learning Program