Question

For a satellite moving in the orbit around the earth, the ratio of kinetic energy to potential energy is

• A. $\frac{1}{\sqrt{2}}$
• B. $2$
• C. $\sqrt{2}$
• D. $\frac{1}{2}$

Answer 1

The correct option is D $\frac{1}{2}$

Potential energy $P.E=\frac{-GMm}{r}$

Kinetic energy $K.E=\frac{GMm}{2r}$

So, $\frac{K.E}{P.E}=\frac{1}{2}$