For a satellite very close to the surface of earth, we get the time period of the satellite equal to

85 minutes

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60 minutes

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40 minutes

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24 minutes

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Solution

The correct option is A $85 minutes$
$T = 2 π \sqrt{\frac{R_{E}}{g}} = 2 π \sqrt{\frac{64 \times 10^{5}}{9.8}} s ≅ 85 minutes$

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