For a scalar function f(x,y,z)=x2+3y2+2z2, the gradient at the point P(1,2,−1) is
A
2^i+6^j+4^k
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B
2^i+12^j−4^k
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C
2^i+12^j+4^k
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D
√56
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Solution
The correct option is B2^i+12^j−4^k Given scalar function, f(x,y,z)=x2+3y2+2z2 gradf=▽f =^i∂f∂x+^j∂f∂y+^k∂f∂z =^i(2x)+^j(6y)+^k(4z) gradf at (1,2,−1) =2^i+12^j−4^k