For a second order reaction rate at a particular time is X. If the initial concentration is tripled, the rate will become:
In a reaction if the concentration of reactant A is tripled, the rate of reaction becomes twenty seven times. What is the order of the reaction?
If a reaction has the experimental rate expression rate = K[A]2[B], if the concentration of A is doubled and the concentration of B is halved, the what happens to the reaction rate:-