Question

For a series LCR circuit, $L=2\text{H},C=32\mu \text{F}$ and $R=10\Omega$. What will be the magnitude of Q-factor at resonance?

• A. $25$
• B. $15$
• C. $50$
• D. $12$

Answer 1

The correct option is A $25$

We know that, at resonance, quality factor,

$Q=\frac{1}{R}\sqrt{\frac{L}{C}}$

$\Rightarrow Q=\frac{1}{10}\sqrt{\frac{2}{32\times {10}^{-6}}}=25$

Hence, option $\left(A\right)$ is the correct answer.