Question

For a sightseeing trip, a tourist selects a country randomly from Argentina, Bangladesh, China, Angola, Russia and Algeria. What is the probability that the name of the selected country will begin with A ?

• A. $\frac{1}{2}$
• B. $\frac{7}{5}$
• C. $\frac{1}{4}$
• D. $\frac{3}{8}$

Answer 1

The correct option is A $\frac{1}{2}$

Sample space ={ Argentina, Bangladesh, China, Angola, Russia, Algeria}

$n\left(S\right)=6$

Let A be the event of getting the name begin with “A”

A = { Argentina, Angola, Algeria}

$n\left(A\right)=3$

Probability of getting the name begin with A,P(A) = $\frac{n\left(A\right)}{n\left(S\right)}$

$=\frac{3}{6}$

$=\frac{1}{2}$