For a single step reaction, $A + 2 B ⟶ P r o d u c t s$ , the molecularity is:

zero

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three

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two

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one

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Solution

The correct option is B three
The minimum number of reacting particles (molecules, atoms or ions) that come together or collide in a rate determining step to form product or products is called the molecularity of a reaction.
So here in this reaction molecularity is 1(A) + 2(B) = 3

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Similar questions

\to

A + 2 B \to C

For a single step reaction to the type A + 2B → E + 2F

2 A + B \mapsto

6 \times 10^{- 3} m o l e^{- 1} l^{- 1} S^{- 1} .

1.2 \times 10^{- 2}

l^{- 1} S^{- 1}

A_{2} + B_{2} ⟶ 2 A B

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