For a sodium atom, the number of electrons with m = 0 will be:
A
2
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B
7
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C
9
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D
8
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Solution
The correct option is B 7 Electronic configuration of sodium is: 1s22s22p63s1 For s orbital, l = 0, m = 0 For p orbital, l = 1, m = +1, 0, -1 Hence, the number of electrons with m = 0 is: 2 (from 1s) + 2 (from 2s) + 2 (from 2p) + 1(from 3s) = 7