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Question

For a sodium atom, the number of electrons with m = 0 will be:

A
2
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B
7
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C
9
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D
8
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Solution

The correct option is B 7
Electronic configuration of sodium is: 1s2 2s2 2p6 3s1
For s orbital, l = 0, m = 0
For p orbital, l = 1, m = +1, 0, -1
Hence, the number of electrons with m = 0 is:
2 (from 1s) + 2 (from 2s) + 2 (from 2p) + 1(from 3s) = 7

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