Question

For a sparingly soluble salt $A_p{B}_q$, the relationship of its solubility product $Ls\to K_{sp}$ with its solubility ($S$) is

• A. $Ls\to K_{sp}=S^{p+q}{\left(pq\right)}^{P+q}$
• B. $Ls=S^{p+q}{p}^p{q}^q$
• C. $Ls\to K_{sp}=S^{p+q}.p^p{q}^q$
• D. $Ls\to K_{sp}=S^{pq}.p^p{q}^q$

Answer 1

The correct option is B $Ls=S^{p+q}{p}^p{q}^q$

For a sparingly soluble salt $A_p{B}_q$, the relationship of its solubility product $Ls\to K_{sp}$ with its solubility ($S$) is $Ls=S^{p+q}{p}^p{q}^q$
Let the solubility be $S$ mol/liter.
$A_p{B}_q\rightleftharpoons \underset{Sp}{p{A}^{q+}}+\underset{Sq}{q{B}^{p-}}$
The solubility product
$Ls=K_{sp}={\left[A^{q+}\right]}^p{\left[B^{p-}\right]}^q={\left[Sp\right]}^p{\left[Sp\right]}^q=p^p.q^q{\left(S\right)}^{p+q}$