Question

For a sparingly soluble salt $A_p{B}_q,$ the relationship its solubility product $\left(K_{sp}\right)$ with its solubility (S) is

• A. $K_{sp}=S^{(p+q)}.p^p.q^q$
• B. $K_{sp}=S^{(p+q)}.p^q.q^p$
• C. $K_{sp}=S^{\left(pq\right)}.p^p.q^q$
• D. $K_{sp}=S^{pq}.(pq{)}^{p+q}$

Answer 1

The correct option is A $K_{sp}=S^{(p+q)}.p^p.q^q$

The sparingly soluble salt ionizes as:
$A_p{B}_q\left(s\right)\rightleftharpoons p{A}^{+q}\left(aq\right)+q{B}^{-p}\left(aq\right)-psqs$
Solubility product $K_{sp}=\left[A^{+q}{]}^p\right[B^{-p}{]}^q{K}_{sp}=(ps{)}^p.(qs{)}^q=p^p.q^q.s^{(p+q)}$