For a spontaneous process, the correct statement(s) is(are)

{(Δ G_{s y s t e m})}_{T, P} > 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(Δ S_{s y s t e m}) + (Δ S_{s u r r o u n d i n g s}) > 0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

{(Δ G_{s y s t e m})}_{T, P} < 0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

{(Δ U_{s y s t e m})}_{T, V} > 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct options are
B $(Δ S_{s y s t e m}) + (Δ S_{s u r r o u n d i n g s}) > 0$
C ${(Δ G_{s y s t e m})}_{T, P} < 0$
For a process to be spontaneous,
$Δ S_{s y s t e m} + Δ S_{s u r r o u n d i n g} > 0$
${(Δ G_{s y s t e m})}_{T, P} < 0$
${(Δ U_{s y s t e m})}_{T, V} < 0$
Spontaneity of the process can be expressed either by taking entropy changes of system and surrounding together or by considering free energy changes of the system alone at constant temperature and pressure.

Suggest Corrections

Similar questions

H_{2} O (l) \to H_{2} O (g) a t T = 100^{\circ} C

Δ G

Δ S_{s y s t e m}

Δ S_{s u r r o u n d i n g s} = 0

Δ H = 0

S_{1}

S_{2}

(Δ G_{s y s t e m})_{T, P} < 0

S_{3}

H_{2} O (l) \to H_{2} O (s)

Δ S_{s y s t e m} = - 22.13, Δ S_{s u r r o u n d i n g} = + 22.05 J / m o l

{(Δ G)}_{T, P} = 0

{(Δ G)}_{T, P} < 0

{(Δ G)}_{U, V} = 0

{(Δ G)}_{U, V} > 0

Join BYJU'S Learning Program