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Standard XII
Chemistry
Gibbs Free Energy & Spontaneity
For a spontan...
Question
For a spontaneous process, which of the following is always true :
a.
Δ
G
>
0
b.
Δ
t
o
t
a
l
S
<
0
c.
T
Δ
S
>
0
d.
Δ
G
<
0
A
a
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B
b
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C
c
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D
d
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Solution
The correct option is
D
d
As we know,
for a spontaneous process,
Δ
G
=
Δ
H
−
T
Δ
S
<
0
and
Δ
t
o
t
a
l
S
>
0
Hence, option D is correct.
Suggest Corrections
0
Similar questions
Q.
Free energy,
G
=
H
−
T
Δ
S
, is a state function that indicates whether a reaction is spontaneous or non-spontaneous. If you think of
T
S
as the part of the system`s energy that is disordered already, then
(
H
−
T
S
)
is the part of the system`s energy that is still ordered and therefore free to cause spontaneous change by becoming disordered.
Also,
Δ
G
=
Δ
H
−
T
Δ
S
From the second law of thermodynamics, a reaction is spontaneous if
Δ
t
o
t
a
l
S
is positive, non-spontaneous if
Δ
t
o
t
a
l
S
is negative, and at equilibrium if
Δ
t
o
t
a
l
S
is zero.
Since
−
T
Δ
S
=
Δ
G
and since
Δ
G
and
Δ
S
have opposite signs, we can restate the Thermodynamic criterion for the spontaneity of a reaction carried out at a constant temperature and pressure.
If
Δ
G
<
0
, the reaction is spontaneous
If
Δ
G
>
0
, the reaction is non-spontaneous
If
Δ
G
=
0
, the reaction is at equilibrium
Read the above paragraph carefully and answer the following questions based on the above comprehension.
Which of the following is correct?
Q.
Free energy,
G
=
H
−
T
Δ
S
, is a state function that indicates whether a reaction is spontaneous or non-spontaneous. If you think of
T
S
as the part of the system`s energy that is disordered already, then
(
H
−
T
S
)
is the part of the system`s energy that is still ordered and therefore free to cause spontaneous change by becoming disordered.
Also,
Δ
G
=
Δ
H
−
T
Δ
S
From the second law of Thermodynamics, a reaction is spontaneous if
Δ
t
o
t
a
l
S
is positive, non-spontaneous if
Δ
t
o
t
a
l
S
is negative, and at equilibrium if
Δ
t
o
t
a
l
S
is zero.
Since,
−
T
Δ
S
=
Δ
G
and since
Δ
G
and
Δ
S
have opposite signs, we can restate the Thermodynamic criterion for the spontaneity of a reaction carried out at a constant temperature and pressure.
If
Δ
G
<
0
, the reaction is spontaneous
If
Δ
G
>
0
, the reaction is non-spontaneous
If
Δ
G
=
0
, the reaction is at equilibrium
Read the above paragraph carefully and answer the following questions based on the above comprehension.
If an endothermic reaction is non-spontaneous at freezing point of water and becomes feasible at its boiling point, then:
Q.
Free energy,
G
=
H
−
T
Δ
S
, is a state function that indicates whether a reaction is spontaneous or non-spontaneous. If you think of
T
S
as the part of the system`s energy that is disordered already, then
(
H
−
T
S
)
is the part of the system`s energy that is still ordered and therefore free to cause spontaneous change by becoming disordered.
Also,
Δ
G
=
Δ
H
−
T
Δ
S
From the second law of Thermodynamics, a reaction is spontaneous if
Δ
t
o
t
a
l
S
is positive, non-spontaneous if
Δ
t
o
t
a
l
S
is negative, and at equilibrium if
Δ
t
o
t
a
l
S
is zero.
Since,
−
T
Δ
S
=
Δ
G
and since
Δ
G
and
Δ
S
have opposite signs, we can restate the Thermodynamic criterion for the spontaneity of a reaction carried out at a constant temperature and pressure.
If
Δ
G
<
0
, the reaction is spontaneous
If
Δ
G
>
0
, the reaction is non-spontaneous
If
Δ
G
=
0
, the reaction is at equilibrium
Read the above paragraph carefully and answer the following questions based on the above comprehension.
One mol of ice is converted to liquid at
273
K
;
H
2
O
(
s
)
and
H
2
O
(
l
)
have entropies
38.20
and
60.03
J
m
o
l
−
1
d
g
−
1
. Enthalpy change in the conversion will be:
Q.
From application of thermodynamics on chemical reaction,
we get
Δ
G
=
Δ
G
0
+
R
T
ln Q
Also
Δ
G
=
Δ
H
−
T
Δ
S
.
If
Δ
G
=
0
, reaction is at equilibrium.
If
Δ
G
>
0
reaction is non-spontaneous under given condition.
I
f
Δ
G
<
0
, reaction is spontaneous under given condition.
Consider the reaction given below.
A
(
s
)
⇌
2
B
(
g
)
Δ
H
0
=
160
KJ/mol.
Δ
S
0
=
400
J/mol-K at
400
K
Which of the following is correct at
400
K?
Q.
Δ
G
=
Δ
H
−
T
Δ
S
.
If true enter 1, else enter 0.
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